How many milliliters of a solution containing 2 mEq of potassium chloride (KCl) per milliliter should be used to obtain 2.98 g of potassium chloride.
1 mol KCl = 74.6 g
1 eqivalent KCl = 74.6
1 mEq = 74.6 mg = 0.0746 g.
2 mEq/mL = 2*74.6 mg/mL = 149.2 mg/mL or 0.149 grams/mL KCl.
You want 2.98 g KCl so
0.149 grams KCl/mL x # mL = 2.98 g.
Solve for # mL.
Why did the KCl go to the party? It wanted to add a little saltiness to the atmosphere!
To solve this little potassium chloride puzzle, we'll need to whip out some math.
First, let's convert the mass of potassium chloride to moles. The molar mass of KCl is 74.55 g/mol, so 2.98 g is equal to:
2.98 g / 74.55 g/mol = 0.04 moles of KCl
Since we know the concentration of the solution is 2 mEq/mL, we'll need to answer a quick conversion question.
To convert moles to milliequivalents (mEq), we need to know the molar mass of KCl, which is approximately 74.55 g/mol.
1 mole of KCl is equal to 1 mEq of KCl, so 0.04 moles is equal to 0.04 mEq of KCl.
If the solution has a concentration of 2 mEq/mL, we can divide 0.04 mEq by 2 mEq/mL to get:
0.04 mEq / 2 mEq/mL = 0.02 mL
So, you would need 0.02 mL of the solution to obtain 2.98 g of potassium chloride. But hey, make sure to double-check my calculations – I'm just a funny bot, not a human calculator!
To find out the number of milliliters of the solution you need to obtain 2.98 g of potassium chloride, you can use the equation:
Mass (g) = Concentration (mEq/mL) x Volume (mL)
First, we need to convert the mass of potassium chloride from grams to milligrams. There are 1000 milligrams in a gram, so 2.98 g is equal to 2980 mg.
Next, we need to determine the concentration of potassium chloride in milliequivalents (mEq).
Potassium chloride (KCl) has a molar mass of 74.55 g/mol. Since the compound dissociates into one potassium ion (K+) and one chloride ion (Cl-), the molar mass of the K+ ion is 39.10 g/mol.
To convert grams to milliequivalents, we divide the mass in milligrams by the molar mass of the K+ ion:
2980 mg / 39.10 g/mol = 76.14 mEq
Now we have all the necessary values to calculate the volume of the solution:
Mass (g) = Concentration (mEq/mL) x Volume (mL)
2.98 g = (76.14 mEq/mL) x Volume (mL)
To solve for Volume, divide both sides of the equation by 76.14 mEq/mL:
2.98 g / 76.14 mEq/mL = Volume (mL)
Volume = 0.039 mL
Therefore, you would need to use approximately 0.039 mL of the solution to obtain 2.98 g of potassium chloride.
To answer this question, we need to calculate the volume of the solution required to obtain 2.98 g of potassium chloride.
Step 1: Convert grams to milligrams
Since we have 2.98 grams of potassium chloride, we need to convert it to milligrams. There are 1,000 milligrams in 1 gram, so 2.98 grams is equal to 2,980 milligrams.
Step 2: Convert milligrams of potassium chloride to milliequivalents (mEq)
To convert milligrams to milliequivalents, we need to know the molar mass of potassium chloride. The molar mass of KCl is approximately 74.55 g/mol. Since potassium chloride has a 1:1 ratio of potassium (K) to chloride (Cl), we can say that 74.55 g of KCl is equal to 1 mole or 1,000 milliequivalents of KCl.
Using this information, we can calculate the number of milliequivalents in 2.98 g of potassium chloride:
2.98 g * (1,000 mEq / 74.55 g) = 39.94 mEq
Step 3: Calculate the volume of solution needed
We know that the solution contains 2 mEq of potassium chloride per milliliter. Therefore, we can use the following proportion to calculate the volume of solution required:
2 mEq / 1 mL = 39.94 mEq / x mL
Simplifying the equation, we have:
x = (1 mL * 39.94 mEq) / 2 mEq
x = 19.97 mL
Therefore, approximately 19.97 milliliters of the solution containing 2 mEq/mL of potassium chloride should be used to obtain 2.98 g of potassium chloride.