A solution contains 100 ppm of lead. Determine the mass of lead present in 0.500 kg of the solution.

1 ppm is 1 mg/kg by definition.

So 100 ppm is 100 mg/kg or 50 mg in 0.500 kg.

To determine the mass of lead present in 0.500 kg of the solution, we need to calculate it based on the concentration of lead in terms of parts per million (ppm).

First, let's convert 0.500 kg to grams since ppm is expressed in terms of mass:

0.500 kg * 1000 g/kg = 500 grams

Now, we can calculate the mass of lead using the ppm value:

ppm means parts per million, which is equivalent to 1 mg/L (milligram per liter). So, 100 ppm of lead in the solution means there are 100 mg of lead in 1 liter of the solution.

To find the mass of lead present in 500 grams of the solution, we can set up a proportion using the ppm value:

100 ppm = 100 mg/L
x ppm = 500 grams

Cross-multiplying the proportion:

x ppm * 100 mg/L = 100 ppm * 500 grams

x ppm = (100 ppm * 500 grams) / 100 mg/L

Simplifying the expression:

x ppm = (100 * 500) ppm

x ppm = 50,000 ppm

Therefore, the mass of lead present in 0.500 kg of the solution is 50,000 ppm.

To determine the mass of lead present in the solution, we need to know the concentration of lead in terms of mass per unit volume.

The given concentration of lead is 100 parts per million (ppm), which means that for every one million parts of the solution, there are 100 parts of lead.

To find the concentration in terms of mass per unit volume, we can convert ppm to milligrams per liter (mg/L), as follows:

1 ppm = 1 mg/L

Now, we know that 0.500 kg of the solution is equivalent to 500 grams.

To calculate the mass of lead in the solution, we can multiply the concentration in mg/L by the volume of the solution in liters. Since we don't have the volume of the solution, we cannot directly find the mass of lead.

However, if we assume that the volume of the solution (in liters) is equal to its mass (in kg), we can use this approximation. This is because the density of water (which is usually the solvent in solutions) is close to 1 g/mL or 1 kg/L.

So, we can approximate the volume of the solution as 0.500 L.

Now, we can calculate the mass of lead in the solution:

Mass of lead = Concentration of lead (mg/L) × Volume of solution (L)

Since the concentration of lead is given as 100 ppm (which we converted to mg/L), the calculation becomes:

Mass of lead = 100 mg/L × 0.500 L

Mass of lead = 50 mg

Therefore, the mass of lead present in 0.500 kg of the solution is approximately 50 milligrams.