Name 2 values of that make the expression factorable
6x^2+bx-11
the discriminant is b^2 + 264
so you need that to be a perfect square
25+264 = 289 = 17^2
6x^2+5x-11 = (6x+11)(x-1)
6x^2-5x-11 = (6x-11)(x+1)
6x^2+bx-11
so you need that to be a perfect square
25+264 = 289 = 17^2
6x^2+5x-11 = (6x+11)(x-1)
6x^2-5x-11 = (6x-11)(x+1)