Find (f-g)(x),given the function f and g,f(x)=3x+4 and g(x)=2x-1 and f(x)=x-1 and g(x)=x-4
(f-g)(x) = f(x)-g(x)
so, for the first pair, f-g = (3x+4)-(2x-1) = x+5
now you do the other pair.
To find (f - g)(x), we need to subtract the function g from the function f.
Given:
f(x) = 3x + 4
g(x) = 2x - 1
To subtract the functions, we substitute the definitions of f(x) and g(x) into (f - g)(x), i.e.,
(f - g)(x) = f(x) - g(x)
= (3x + 4) - (2x - 1)
Next, we simplify the expression by distributing the negative sign to every term inside the parentheses:
(f - g)(x) = 3x + 4 - 2x + 1
Now we combine like terms to simplify further:
(f - g)(x) = (3x - 2x) + (4 + 1)
= x + 5
Therefore, (f - g)(x) = x + 5.
To find (f-g)(x), we need to subtract the value of g(x) from f(x) for a given input x.
Given:
f(x) = 3x + 4
g(x) = 2x - 1
To find (f-g)(x), we substitute the values of f(x) and g(x) into the expression:
(f-g)(x) = f(x) - g(x)
Substituting the expressions for f(x) and g(x):
(f-g)(x) = (3x + 4) - (2x - 1)
Now, let's simplify the expression by applying the distributive property:
(f-g)(x) = 3x + 4 - 2x + 1
Combine like terms:
(f-g)(x) = (3x - 2x) + (4 + 1)
(f-g)(x) = x + 5
Therefore, (f-g)(x) = x + 5.