Using equation show the formation of hydrozonium ion in an aqueous solution of hydrogen chloride and tetraoxosulphate (iv)acid
H2SO4 + H2O ==> 2[H3O]^+ + [SO4]^2-
FYI.
1. There is no such compound as tetraoxosulphate (iv)acid. You COULD mean H2SO3 but that isn't the correct name. A correct IUPAC name for H2SO3 is sulfurous acid but there are other correct names for that as well.
You could NOT have meant H2SO4 since S is +6 and not +4 in sulfuric acid.
2. I have never heard of hydrozonium ion. I think you must have meant hydronium ion which is [H3O]^+
3. Back to H2SO3, it COULD be called, correctly, dihydroxidooxidosulfur or dihydrogen sulfite or sulfurous acid but NOT tetraoxosulfate(iv) acid.
The formation of the hydronium ion (H3O+) in an aqueous solution of hydrogen chloride (HCl) and tetraoxosulfate (IV) acid (H2SO4) can be represented by an equation.
First, let's break down the dissociation of hydrogen chloride and tetraoxosulfate (IV) acid in water:
HCl → H+ + Cl-
H2SO4 → 2H+ + SO4^2-
Now, when both hydrogen chloride and tetraoxosulfate (IV) acid are added to water, the following reactions occur:
HCl + H2O → H3O+ + Cl-
H2SO4 + 2H2O → 2H3O+ + SO4^2-
Therefore, the formation of the hydronium ion (H3O+) in an aqueous solution of hydrogen chloride and tetraoxosulfate (IV) acid can be represented as:
HCl + H2SO4 + 2H2O → 3H3O+ + Cl- + SO4^2-
This equation shows how the hydrogen ions from both acids combine with water molecules to form hydronium ions (H3O+). The chloride ion (Cl-) and sulfate ion (SO4^2-) remain in the solution as counterions.