Question

Consider the function f(x)= 4x^2-8x+6,0<=x<=6

The absolute maximum of f(x) (on the interval) is at x=
and the absolute maximum of f(x) (on the interval) is at x=

The absolute minimum of f(x) (on the interval) is at x=
and the absolute minimum of f(x) (on the interval) is at x=

Answer 1

Don't forget what you know about parabolas.

The vertex is at -b/2a = 1. Since a>0, this will be the min
so now find f(0) and f(6) to get the max
Or, knowing that the axis of symmetry is at x=1, you know that f(6) > f(0) because it is farther from the vertex.