Use Theorem 9.11 to determine the convergence or divergence of the p-series.
1+ 1/6root2 + 1/6root3 + 1/6root4 +...
p=
not sure what the theorem is, but we do know that
∑ 1/n^p
diverges for p <= 1
Your sequence is basically ∑ 1/n^(1/2)
1+ 1/6root2 + 1/6root3 + 1/6root4 +...
p=
∑ 1/n^p
diverges for p <= 1
Your sequence is basically ∑ 1/n^(1/2)