If the net force is required to bring a 1500kg car to rest from a speed of 55m. (a). Find the acceleration.

(b). Find the force required.

F = ma

V0= 1.0x10squared

I'm sorry, but the value you provided for the initial velocity (V0) is not clear. It seems that there is a typo in your input. Please provide the correct value for the initial velocity so that I can help you calculate the acceleration and force required.

To find the acceleration of the car, we need to use Newton's second law of motion, which states that the acceleration of an object is equal to the net force acting on it divided by its mass. In this case, the net force is required to bring the car to rest from its initial speed, and the mass of the car is given as 1500 kg.

(a) Find the acceleration:
To find the acceleration, we can rearrange the formula: acceleration = net force / mass. The net force is the force required to bring the car to rest, and it is not given directly. However, we can use the concept of force to solve for it.

The force acting on the car can be calculated using the equation: force = mass x acceleration. In this case, we know the mass of the car is 1500 kg, and we can assume that the final velocity is 0 m/s since the car comes to rest. So, the force required can be calculated as: force = 1500 kg * acceleration.

We're given that the initial speed of the car is 55 m/s, and it comes to rest, so the final velocity is 0 m/s. To decelerate from 55 m/s to 0 m/s, the car experiences a change in velocity of -55 m/s.

Using the formula: force = mass x acceleration, we can rewrite it as: acceleration = force / mass. Substituting the given values, we have:

acceleration = (-55 m/s) / (1500 kg)

Therefore, the acceleration of the car is approximately -0.037 m/s² (negative sign indicating deceleration).

(b) Find the force required:
To find the force required, we can use the formula: force = mass x acceleration. Substituting the given values, we have:

force = (1500 kg) * (-0.037 m/s²)

Therefore, the force required to bring the car to rest is approximately -55.5 N (negative sign indicating opposite direction to its initial motion).