A target lies a distance R = 1100 m from a cannon across level ground, and a distance d = 780 m behind a wall h = 400 m tall. If the cannon shoots projectiles with speed 160 m/s, at what angle should the cannon fire so as to hit the target over the wall?

Question

A target lies a distance R = 1100 m from a cannon across level ground, and a distance d = 780 m behind a wall h = 400 m tall.  If the cannon shoots projectiles with speed 160 m/s, at what angle should the cannon fire so as to hit the target over the wall?

oobleck · Accepted Answer

You know that y = -g/(2(vcosθ)^2) x^2 + tanθ x y = -4.9/(160 cosθ)^2 x^2 + tanθ x You know that you need y(1100) = 0 so θ = 12.5° or 77.5° If we use 12.5°, y(320) = 50 and we need it to be 400 So, if we use 77.5°, y(320) = 1026 So that will work nicely.