what is the least multiple of 4 that can be formed using all the digits 4, 0, 2, 6, and 1 only once?
well, it can't start with 0, so it will be 2000 + something
since 2000 is a multiple of 4, what other multiple of 4 can be formed using the digits 4 and 6?
Thank you
To find the least multiple of 4 that can be formed using all the digits 4, 0, 2, 6, and 1 only once, we need to determine the possible combinations of these digits and check if they are divisible by 4.
Let's start by listing all the possible combinations:
1. 4026
2. 4062
3. 4102
4. 4120
5. 4160
6. 4206
7. 4260
8. 4602
9. 4620
10. 4602
11. 4610
Next, we need to check if these numbers are divisible by 4. A number is divisible by 4 if the last two digits are divisible by 4.
Checking the combinations, we find that the numbers 4026, 4062, 4160, and 4260 are all divisible by 4.
However, we want to find the least multiple, so the smallest number among these is 4026.
Therefore, the least multiple of 4 that can be formed using all the digits 4, 0, 2, 6, and 1 only once is 4026.
To find the least multiple of 4 that can be formed using all the digits 4, 0, 2, 6, and 1 only once, we can try different combinations of these digits.
Since a number is divisible by 4 if the last two digits are divisible by 4, we need to find a combination of these digits that creates a number whose last two digits are divisible by 4.
We can start by arranging the digits in decreasing order, which gives us 64201. We can then check if this number is divisible by 4 by checking if the last two digits, 01, are divisible by 4. Since 01 is not divisible by 4, we need to try a different combination.
The next step is to find the next largest number that ends with 2, which is 42106. Again, we check if the last two digits, 06, are divisible by 4. Fortunately, 06 is divisible by 4, so we have found our answer.
Therefore, the least multiple of 4 that can be formed using all the digits 4, 0, 2, 6, and 1 only once is 42,106.