What is the distance between P(-4,3) and Q(6,1)? Round your answer to the nearest tenth.
per the usual formula, that would be
√((6+4)^2 + (1-3)^2) = √ 104
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To find the distance between two points in a coordinate plane, we can use the distance formula. The distance formula is derived from the Pythagorean theorem and is given by:
d = sqrt((x2 - x1)^2 + (y2 - y1)^2)
Where (x1, y1) and (x2, y2) are the coordinates of the two points, and d is the distance between them.
In this case, the coordinates of point P are (-4, 3), and the coordinates of point Q are (6, 1).
So, we can substitute the values into the distance formula:
d = sqrt((6 - (-4))^2 + (1 - 3)^2)
Simplifying further:
d = sqrt((10)^2 + (-2)^2)
= sqrt(100 + 4)
= sqrt(104)
Rounding to the nearest tenth, the distance between P(-4, 3) and Q(6, 1) is approximately 10.2 units.