The back end of a 160-metre-long train disappears into a 700-metre-long tunnel. Twenty seconds later
the front of the train emerges from the tunnel. Determine the speed of the train in m/s.
So the front of the 160 m long train took 20 seconds to go (700-160) m.
since speed = distance/time .........
Well, it seems like that train really knows how to play hide and seek! Let's calculate its speed.
First, we need to determine the time it takes for the entire train to pass through the tunnel. The length of the tunnel is 700 meters, and we know that it takes the front of the train 20 seconds to travel that distance. So, the back of the train, which is 160 meters behind the front, will take an additional 20 seconds to pass through the tunnel.
Total time = 20 seconds (front of the train) + 20 seconds (back of the train) = 40 seconds
Now, we can find the speed of the train by dividing the total distance traveled by the time taken.
Total distance traveled = Length of the train + Length of the tunnel
= 160 meters (train) + 700 meters (tunnel)
= 860 meters
Speed of the train = Total distance traveled / Time taken
= 860 meters / 40 seconds
= 21.5 meters per second
So, the speed of the train is 21.5 m/s. But be careful, it might be good at disappearing acts!
To determine the speed of the train, we need to find the time it takes for the entire train to pass through the tunnel.
Let's assume the speed of the train is "v" m/s.
The length of the train is given as 160 meters, and the length of the tunnel is given as 700 meters.
Since both the back end and the front of the train are completely inside the tunnel for 20 seconds, we can write the following equation:
Time = Distance / Speed
For the back end of the train to completely clear the tunnel, its distance traveled is 160 meters (length of the train) + 700 meters (length of the tunnel). The time taken is 20 seconds.
Using the equation, we can write:
(160 + 700) / v = 20
Simplifying the equation:
860 / v = 20
To find the speed "v," we rearrange the equation:
v = 860 / 20
Evaluating the right side of the equation:
v = 43 m/s
Therefore, the speed of the train is 43 m/s.
To determine the speed of the train, we need to find the distance it travels in 20 seconds.
Let's break down the problem:
1. The train is 160 meters long, and the back of the train disappears into a 700-meter-long tunnel. So the total distance the train covers while inside the tunnel is 160 + 700 = 860 meters.
2. We know that the front of the train emerges from the tunnel 20 seconds after the back of the train disappears into it.
Now, to find the speed of the train in meters per second, we will use the following formula:
Speed = Distance/Time
Speed = 860 meters / 20 seconds
Calculating this, we find that the speed of the train is:
Speed = 43 meters per second (m/s).
Therefore, the speed of the train is 43 m/s.