3 batteries cost $5r and 8 folders cost $2r. Jason bought 6 batteries and 4 folders how much does he pay. Give answer in terms of r
6 = 2 *3
so 6 batteries cost 2 * cost of 3 batteries
which is 10 r
then 4 folders costs 1/2 as much as 8 folders
so 1 r
10 r + 1 r = 11 r
or...
cost of 1 battery = 5/3 r
cost of 1 folder = 2/8 r = r/4
cost of 6 batteries and 4 folders
= 6(5/3)r + 4(r/4) = 10r + r = 11r
To find out how much Jason pays, we need to calculate the cost of 6 batteries and 4 folders separately.
The cost of 6 batteries can be calculated by multiplying the cost of 1 battery by 6:
6 batteries = 6 * 1 battery = 6r
The cost of 4 folders can be calculated by multiplying the cost of 1 folder by 4:
4 folders = 4 * 0.25 folder = 0.25r
To find out how much Jason pays in total, we add the cost of the batteries and the cost of the folders:
Total cost = Cost of batteries + Cost of folders = 6r + 0.25r = 6.25r
Therefore, Jason pays 6.25r in total.
To find out how much Jason pays for 6 batteries and 4 folders, we need to calculate the cost of each component separately and then add them together.
Given that 3 batteries cost $5r, we can calculate the cost of 1 battery by dividing the total cost by the number of batteries:
Cost of 1 battery = $5r / 3 = $1.67r
Similarly, given that 8 folders cost $2r, we can calculate the cost of 1 folder by dividing the total cost by the number of folders:
Cost of 1 folder = $2r / 8 = $0.25r
Now, we can find the total cost by multiplying the cost of each component by the respective quantities and adding them together:
Total cost = (Cost of 6 batteries × Quantity of batteries) + (Cost of 4 folders × Quantity of folders)
Total cost = ($1.67r × 6) + ($0.25r × 4)
Total cost = $10.02r + $1.00r
Total cost = $11.02r
So, Jason will pay $11.02r for 6 batteries and 4 folders.