A bag contains a number of pieces of candy, of which 78 are red, 24 are brown, and the remainder is yellow. If the probability of selecting a yellow 1 piece of candy from this bag at random is how 3 many yellow pieces of candy are in the bag?
To determine the number of yellow pieces of candy in the bag, we need to use the information given.
We know that the bag contains 78 red pieces and 24 brown pieces. The total number of candies in the bag is the sum of the red, brown, and yellow candies.
Let's assume the number of yellow candies is y. So, the total number of candies in the bag is 78 + 24 + y.
The probability of selecting a yellow candy at random is defined as the ratio of the number of yellow candies to the total number of candies in the bag.
So, the probability can be expressed as:
P(yellow) = y / (78 + 24 + y)
We are given that the probability of selecting a yellow candy is 3/10.
Therefore, we can write this as an equation:
3/10 = y / (78 + 24 + y)
To solve for y, we can cross-multiply:
(3/10) * (78 + 24 + y) = y
Distributing the (3/10):
(3/10) * 102 + (3/10) * y = y
Rearranging the equation:
30.6 + (3/10) * y = y
Subtracting (3/10) * y from both sides:
30.6 = (7/10) * y
To isolate y, we divide both sides by (7/10):
y = 30.6 / (7/10)
Evaluating the division:
y ≈ 43.71
Therefore, there are approximately 43 yellow pieces of candy in the bag.
Your posting is gibberish. Maybe you can get some help if you make it understandable. You have provided incomplete information and asked questions that make no sense.
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