Find the length of the line segment joining the points (−2, 4) and (3, 6)
(-2, 4) --> (x1, y1)
(3, 6) --> (x2, y2)
Using the distance of a line formula (derived from the Pythagorean Theorem):
d = sqrt[(x2-x1)² + (y2-y1)²]
d = sqrt[(3-(-2))² + (6-4)²]
d = sqrt[(3+2)² + (6-4)²]
d = sqrt[(5)² + (2)²]
d = sqrt[25 + 4]
∴d = sqrt(29) ≈ 5.39 units
Ok I got it
To find the length of the line segment joining two points in a coordinate plane, we can use the distance formula:
The distance formula is given by:
d = √((x2 - x1)^2 + (y2 - y1)^2)
Let's use this formula to find the length of the line segment joining the points (-2, 4) and (3, 6):
First, we identify the coordinates of the two points:
Point 1: (-2, 4) -> (x1, y1)
Point 2: (3, 6) -> (x2, y2)
Next, we substitute these values into the distance formula:
d = √((x2 - x1)^2 + (y2 - y1)^2)
= √((3 - (-2))^2 + (6 - 4)^2)
= √((3 + 2)^2 + (6 - 4)^2)
= √((5)^2 + (2)^2)
= √(25 + 4)
= √29
Therefore, the length of the line segment joining the points (-2, 4) and (3, 6) is √29.