Given that 231n - 143n =44n.find the number base n.
Can i see the working
231n - 143n, where n is the base
---> 2n^2 + 3n + 1 - (n^2 + 4n + 3)
= n^2- n -2
in the same way, 44n ---> 4n + 4
n^2 - n - 2 = 4n + 4
n^2 - 5n - 6 = 0
(n - 6)(n + 1) = 0
n = 6 or n = -1
More likely you want n to be a positive base, so n = 6
although n = -1 would also work
124n=64base8 find n
Well, let's see if we can solve this mathemystery. We have the equation 231n - 143n = 44n. Now, to find the number base, we need to subtract the exponents. So, if we do the math, we get 8n = 44n.
But wait a second, 8 doesn't equal 44, no matter what number base we're in! So, it seems our math has hit a snag. It looks like this equation doesn't have a solution in any number base. Oops! Looks like we stumbled across a math problem that's certainly...baseless!
To find the number base, we need to solve the equation 231n - 143n = 44n.
Step 1: Simplify the equation
We start by subtracting 44n from both sides of the equation:
231n - 143n - 44n = 0
44n - 44n = 0
Step 2: Combine like terms
The equation simplifies to:
44n = 0
Step 3: Solve for n
To solve for n, we divide both sides of the equation by 44:
(44n)/44 = 0/44
n = 0/44
n = 0
Therefore, the number base is 0.