Enter a balanced equation for the reaction between aqueous lead(II) nitrite and aqueous lithium bromide to form solid lead(II) bromide and aqueous lithium nitrite.
first step: look up the formula for each compound.
come back with your equation if you get stuck.
To write a balanced equation for the reaction, we need to ensure that the number of atoms of each element is the same on both sides of the equation.
The reaction between aqueous lead(II) nitrite (Pb(NO2)2) and aqueous lithium bromide (LiBr) can be represented by the following balanced equation:
2Pb(NO2)2(aq) + 2LiBr(aq) → PbBr2(s) + 2LiNO2(aq)
This equation shows that two moles of lead(II) nitrite react with two moles of lithium bromide to produce one mole of lead(II) bromide and two moles of lithium nitrite.
To balance the chemical equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation.
The molecular formula for aqueous lead(II) nitrite is Pb(NO2)2, and for aqueous lithium bromide is LiBr. The solid lead(II) bromide is PbBr2, and aqueous lithium nitrite is LiNO2.
The unbalanced equation can be written as follows:
Pb(NO2)2 + LiBr → PbBr2 + LiNO2
To balance the equation, follow these steps:
1. Count the number of each type of atom on both sides of the equation.
Left side (Reactants):
Pb: 1
N: 2
O: 4
Li: 1
Br: 1
Right side (Products):
Pb: 1
N: 1
O: 2
Li: 1
Br: 2
2. Start by balancing the atoms that appear in the lowest number.
In this case, the Pb and Li are already balanced.
3. Balance the nitrogen (N) atoms next.
To do this, multiply the coefficient of LiNO2 by 2 to balance the nitrogen atoms on both sides of the equation:
Pb(NO2)2 + LiBr → PbBr2 + 2LiNO2
4. Finally, balance the oxygen (O) atoms by adjusting the coefficient of Pb(NO2)2:
Pb(NO2)2 + 2LiBr → PbBr2 + 2LiNO2
Now, the equation is balanced, with equal numbers of atoms on both sides:
Aqueous lead(II) nitrite + Aqueous lithium bromide → Solid lead(II) bromide + Aqueous lithium nitrite
Pb(NO2)2 + 2LiBr → PbBr2 + 2LiNO2