H2SO4+NAOH=NA2SO4+H2O
The equation is unbalanced. On the left, you have
H: 2+1
S: 1
O: 4+1
Na: 1
on the right you have
H: 2
S: 1
O: 4+1
Na: 2
So, what can you do to fix that? The S is balanced.
What if you try 2NaOH?
This is the nuttiest LCM problem I've seen. Looks like a chemistry problem to me.
The balanced chemical equation for the reaction between sulfuric acid (H2SO4) and sodium hydroxide (NaOH) is:
H2SO4 + 2NaOH → Na2SO4 + 2H2O
To understand how this equation is balanced, let's go step by step:
1. Start by counting the number of atoms on each side of the equation:
- On the left side:
- Hydrogen (H): 2 atoms
- Sulfur (S): 1 atom
- Oxygen (O): 4 atoms
- Sodium (Na): 0 atoms
- On the right side:
- Hydrogen (H): 4 atoms
- Sulfur (S): 1 atom
- Oxygen (O): 4 atoms
- Sodium (Na): 2 atoms
2. Balance the atoms one by one, starting with sodium (Na):
- There are 2 sodium atoms on the right side, but none on the left side, so we need to add a coefficient of 2 in front of NaOH:
H2SO4 + 2NaOH → Na2SO4 + 2H2O
3. Now let's balance the hydrogen (H) and oxygen (O) atoms:
- On the left side, there are 2 hydrogen atoms and 4 oxygen atoms.
- On the right side, there are 4 hydrogen atoms and 4 oxygen atoms.
- The hydrogen and oxygen atoms are already balanced.
4. Lastly, balance the sulfur (S) atom:
- On both sides, there is 1 sulfur atom.
- The sulfur atom is already balanced.
Therefore, the balanced equation for the reaction between H2SO4 and NaOH is:
H2SO4 + 2NaOH → Na2SO4 + 2H2O