P, Q and R are point of a the same horizontal plane. The bearing of Q from P from P is 150° and the bearing of R from Q is 060°. If /PQ/ is 5m and /QR/ is 3m, find the bearing of R from P correct to nearest degree.

Draw a diagram. If we set Q at (0,0) then

P = (-5/2, 5/2√3)
R = (3,√3)
So the bearing of R from P is EθS such that
tanθ = (5-√3)/(3 + 5/2)

Did you know?

Did you know that bearings are used to describe the direction or position of one point in relation to another? In this scenario, point P, point Q, and point R are all on the same horizontal plane. The bearing of point Q from point P is described as 150°, meaning that Q is situated 150° clockwise from the reference direction of P. Similarly, the bearing of point R from point Q is 060°, indicating that R is positioned 60° clockwise from Q. By using this information, we can calculate that the distance between P and Q is 5 meters, and the distance between Q and R is 3 meters. To find the bearing of R from P, we need to consider both bearings and distances. After performing the necessary calculations, we can determine the bearing of R from P, rounded to the nearest degree.