Question

An explorer walks 50 km to the north and then 30 km west. What are the magnitude and direction of his displacement?

A. 58 km, 31 degrees West of North
B. 80 km, NorthWest
C. 58 km 31 degrees North of West
D. 3400 km, northwest

Answer 1

distance: √(50^2+30^2)

direction: θ° W of N where tanθ = 30/50