Out of 7500 students, 75% are offered english and 45% are offered maths. How many are offered both?
not enough information for a solution
if x% do both, then
75+45-x = 100
x = 20%
0.20 * 7500 = 1500
oobleck's implicit assumption is that all students are offered
... english or math or both
25% are not offered english, and 55% are not offered math
... some students may not be offered either
To find out how many students are offered both English and Math, we need to calculate the intersection of the two groups. We can do this by finding the product of the percentages and the total number of students.
First, let's calculate the number of students offered English. We multiply the percentage (75%) by the total number of students (7,500):
Number of students offered English = 75% × 7,500
= (75/100) × 7,500
= 0.75 × 7,500
= 5,625
Next, let's calculate the number of students offered Math. We multiply the percentage (45%) by the total number of students (7,500):
Number of students offered Math = 45% × 7,500
= (45/100) × 7,500
= 0.45 × 7,500
= 3,375
Now, to find out how many students are offered both English and Math, we need to find the intersection between the two groups. We can do this by multiplying the percentages (75% and 45%) and the total number of students (7,500):
Number of students offered both = 75% × 45% × 7,500
= (75/100) × (45/100) × 7,500
= 0.75 × 0.45 × 7,500
= 2,531.25
Therefore, approximately 2,531 students are offered both English and Math.