For a given machine the load moves 2 m when the effort moves 8m,if an effort of 20 N is used to raise a load of 60N, what is the efficiency of the machine
A certain machine has an efficiency of 80%. If the load moves a distance of 2m as the effort moves 8m, how large a force is required to lift a load of 320 New ton
if 100% efficient then 60 *2/8 = 60/4 = 15 N
it actually took you 20 N
100 * 15/20 = 5*15 = 75%
The mechanical advantage of a simple machine is 4.the machine lifts load of 1000 New Ton. What is the force that act's on the machine?
To determine the efficiency of the machine, we first need to calculate the mechanical advantage. Mechanical advantage is the ratio of the load distance to the effort distance.
Given that the load moves 2 m when the effort moves 8 m, the mechanical advantage can be calculated as follows:
Mechanical advantage = Load distance / Effort distance
= 2 m / 8 m
= 1/4
Now, the mechanical advantage can also be calculated as the ratio of the load to the effort:
Mechanical advantage = Load / Effort
= 60 N / 20 N
= 3/1
Since both calculations give the same mechanical advantage, we can conclude that the mechanical advantage of the machine is 1/4 or 3/1.
The efficiency of a machine is defined as the ratio of output work to input work, expressed as a percentage. In this case, the load is the output work while the effort is the input work.
Efficiency = (Output work / Input work) * 100%
The output work can be calculated as the product of the load and the load distance:
Output work = Load * Load distance
= 60 N * 2 m
= 120 Nm
The input work can be calculated as the product of the effort and the effort distance:
Input work = Effort * Effort distance
= 20 N * 8 m
= 160 Nm
Now, we can substitute the values into the efficiency formula:
Efficiency = (Output work / Input work) * 100%
= (120 Nm / 160 Nm) * 100%
= 0.75 * 100%
= 75%
Therefore, the efficiency of the machine is 75%.