Given that= Y(multiples of 3 less than 20),find the number proper subset of Y?
Y = {3,6,9,12,15,18} , so 6 of them
number of subsets = 2^6, including the null set and all of the elements
Use the definition of "proper subset" that you learned to finetune the answer.
3,6,9,12,15,18
3,6,9,12,15,19
Ah, I see you want to find the number of proper subsets of the set Y, which consists of all the multiples of 3 less than 20. Well, let's grab our clown nose and dive right in!
To find the number of proper subsets of Y, we need to keep in mind that a proper subset is defined as a subset that is not equal to the original set Y. So, we need to exclude the empty set and the set Y itself.
Now, let's take a look at the elements in Y. Since Y consists of multiples of 3 less than 20, we have the numbers 3, 6, 9, 12, 15, and 18.
To build a proper subset, we have two choices for each element: we can either include it in the subset or exclude it. For example, for 3, we can either include it in our subset or exclude it. The same goes for each of the other elements.
So, for each of the 6 elements, we can either choose to include it or exclude it, giving us a total of 2^6 = 64 possible subsets.
But remember, we need to exclude the empty set and the set Y itself. So, out of the 64 possible subsets, we subtract the 2 sets we want to exclude, giving us a total of 62 proper subsets of Y.
So, there you have it! The number of proper subsets of Y is 62. But remember, these subsets are just like clown tricks – they might make you laugh, but they should always be handled with care!
To find the number of proper subsets of set Y, we first need to determine the number of elements in the set Y.
Set Y consists of multiples of 3 less than 20. We can find these multiples by starting from 3 and incrementing by 3 until we reach a number less than 20. The multiples of 3 less than 20 are: 3, 6, 9, 12, 15, and 18.
Therefore, set Y = {3, 6, 9, 12, 15, 18}, which contains 6 elements.
To calculate the number of proper subsets, we can use the formula 2^n, where n is the number of elements in the set. Since Y has 6 elements, the number of proper subsets is 2^6 = 64.
Therefore, there are 64 proper subsets of set Y.