find the first 4 terms of the sequence represented by the expression 4 + 3n
a. 2, 5, 8, 11
b. 7, 10, 13, 16
c. 5, 7, 9, 11
d. 4, 6, 9, 12
To find the first 4 terms of the sequence represented by the expression 4 + 3n, we substitute different values of n into the expression.
For n = 1, the expression becomes 4 + 3(1) = 7.
For n = 2, the expression becomes 4 + 3(2) = 10.
For n = 3, the expression becomes 4 + 3(3) = 13.
For n = 4, the expression becomes 4 + 3(4) = 16.
The first 4 terms of the sequence are 7, 10, 13, 16.
Therefore, the answer is b. 7, 10, 13, 16.
To find the first 4 terms of the sequence represented by the expression 4 + 3n, we need to substitute the values of n from 1 to 4 and evaluate the expression.
Let's substitute n = 1:
Term 1 = 4 + 3(1) = 4 + 3 = 7
Next, let's substitute n = 2:
Term 2 = 4 + 3(2) = 4 + 6 = 10
Now, let's substitute n = 3:
Term 3 = 4 + 3(3) = 4 + 9 = 13
Lastly, let's substitute n = 4:
Term 4 = 4 + 3(4) = 4 + 12 = 16
The first 4 terms of the sequence represented by the expression 4 + 3n are 7, 10, 13, and 16.
So, the correct answer is b. 7, 10, 13, 16.
really? try using the values of n, from 1 to 4
4+3(1) = 4+3 = 7
Well, you could check the rest, but only B starts with a 7.
But note that each term is 3 more than the previous one, which reflects the "3n" in the formula.