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A woman is twice as old as her daughter. Five years ago the ratio of their ages was 7:3. Calculate the age of

A. Mother
B. Daughter

m = 2d

(m-5)/(d-5) = 7/3
now finish it off

Did you know?

Did you know that you can use a ratio and some algebra to find the ages of a mother and daughter? In this case, let's say the daughter's age is x. According to the information given, the mother's age is twice that, so it would be 2x. Now, we are told that five years ago, the ratio of their ages was 7:3. To calculate their ages, we subtract 5 from both the daughter's and mother's ages. So, the updated ages are x - 5 for the daughter and 2x - 5 for the mother. Since the ratio of their ages five years ago was 7:3, we can set up an equation: (2x - 5) / (x - 5) = 7/3. To solve this equation, we can cross-multiply: 3(2x - 5) = 7(x - 5). Simplifying this further, we get 6x - 15 = 7x - 35. Rearranging the equation, we have x = 20. Hence, the daughter is 20 years old, and the mother is twice that, which means she is 2 * 20 = 40 years old.