Robin had 4 times as much money as Shawn at first. After spending some money, Robin realized that Shawn had twice as much as he had. If Robin had $48 at first, how much did Robin have in the end?
To solve this problem, let's break it down step by step:
1. Let's define the initial amount of money that Shawn had as "x".
- Since Robin had 4 times as much money as Shawn at first, Robin had 4x dollars.
- Given that Robin had $48 at first, we can set up the equation: 4x = 48
2. Solving the equation to find the value of "x":
- Divide both sides of the equation by 4: 4x/4 = 48/4
- Simplifying gives us: x = 12
3. Now that we know the initial amount of money Shawn had was $12, we need to find the final amount of money that Robin had.
- We're given that after spending some money, Shawn had twice as much money as Robin.
- So Robin had x dollars left, and Shawn had 2x dollars.
4. To find the final amount of money Robin had, we need to subtract the money Robin spent from his initial amount.
- Robin initially had $48, and we found that Shawn initially had $12.
- So Robin spent $48 - $12 = $36.
5. Subtracting the money Robin spent from his initial amount gives us the final amount of money he had:
- Robin had $48 - $36 = $12 in the end.
Therefore, Robin had $12 in the end.