A cylindrical block has a length of 0.18 m, a uniform cross-sectional area of 3.8 × 10 -4m 2and a density of 1250 kgm -3 . The block is suspended from a spring balance and fully immersed in a liquid with a density of 750 kgm -3.
i) Calculate the mass of the block
ii) Calculate the weight of the block
Show how to work out this problem with answers
1.00kg 3.80×10^3 m^3
To calculate the mass of the block, you can use the formula: mass = density * volume.
Given:
Density of the block, ρ_block = 1250 kg/m^3
Cross-sectional area of the block, A = 3.8 × 10^-4 m^2
Length of the block, L = 0.18 m
The volume of the block, V_block, can be calculated using the formula: V_block = A * L.
Substituting the given values, we get:
V_block = (3.8 × 10^-4 m^2) * (0.18 m)
Next, the mass of the block, m_block, can be calculated by multiplying the density of the block and the volume of the block:
m_block = ρ_block * V_block
Substituting the given values, we get:
m_block = (1250 kg/m^3) * V_block
Finally, calculating the mass of the block by substituting the value of V_block, we get the answer to part i).
To calculate the weight of the block, you can use the formula: weight = mass * acceleration due to gravity.
Given:
Mass of the block, m_block (from part i)
Acceleration due to gravity, g = 9.8 m/s^2
Using the formula, weight = m_block * g, we can calculate the weight of the block by substituting the values of m_block and g. This will give us the answer to part ii).