Question

Calculate the value of a, A and C in triangle ABC given that b=17.23cm c=10.86 and B=101°

Answer 1

sin C / c = sin B/b

sin C = (10.86 /17.23) sin 101 = 0.6187
C = 38.2 degrees
then
101 + 38.2 + A = 180
A = 40.8 degrees
then
sin A/a = sin B/b
so
a = b sin A / sin B