Find the equation of a line tangent to the curve xy=√xy-x + 1 at the point (1, 2).
A. y= 2-x
B. y = 5-3x
C. y = 5.667 - 2.667x
D. y= 2.667 - 1.333x
E. y = 2.667 - 1.667x
see your earlier post, where I assumed you meant
xy = √(xy-x) + 1
That didn't work out too well.
In the future, make corrections in the original post, rather than starting a duplicate thread.