A ball of Mass 8kg falls from rest from a height 100m neglecing air resistance calculate it's total energy after falling a distance of 40m

defining potential energy as zero at the ground

m g h = 8 * 9.81 * 100

the sum of kinetic and potential energy is constant during the fall.

In other words they are trying to trick you.

Did you know?

Did you know that the total energy of a falling object can be calculated by considering its initial potential energy and the work done against gravity while falling? For instance, if an 8kg ball is dropped from a height of 100m without air resistance and then falls a distance of 40m, its total energy after falling can be determined. By using the principle of conservation of energy, we can find that the ball's initial potential energy is given by mgh, where m represents the mass (8kg), g is the acceleration due to gravity (9.8m/s^2), and h is the initial height (100m). Thus, the initial potential energy is (8kg)(9.8m/s^2)(100m) = 7,840 Joules. As the ball falls a distance of 40m, its potential energy decreases by mgh, therefore the potential energy after falling a distance of 40m is (8kg)(9.8m/s^2)(40m) = 3,136 Joules. Therefore, the total energy after falling 40m is given by the sum of the potential energy and the kinetic energy.