a 6.0 kW electric oven is connected to a fuse box by a cable of resistance 0.25 ohms. when the cooker is switched on at full power, a current of 26 A passes through it.
Calculate the potential difference between the two ends of the cable and the power wasted in it because of the heating effect of the current.
Calculate the current wasted in the cable because of the heating effect of the current
To calculate the potential difference between the two ends of the cable, you can use Ohm's law, which states that V = I * R, where V is the potential difference, I is the current, and R is the resistance.
In this case, the current passing through the cable is 26 A, and the resistance of the cable is 0.25 ohms. Thus, the potential difference across the cable can be calculated as follows:
V = I * R
V = 26 A * 0.25 ohms
V = 6.5 volts
Therefore, the potential difference between the two ends of the cable is 6.5 volts.
To calculate the power wasted in the cable due to the heating effect of the current, you can use the formula P = I^2 * R, where P is the power, I is the current, and R is the resistance.
In this case, the current passing through the cable is 26 A, and the resistance of the cable is 0.25 ohms. Thus, the power wasted in the cable can be calculated as follows:
P = I^2 * R
P = (26 A)^2 * 0.25 ohms
P = 169 watts
Therefore, the power wasted in the cable due to the heating effect of the current is 169 watts.
However, there is no such thing as "current wasted" in the cable due to the heating effect. The cable heats up due to the resistance in it, which is required for the flow of current. The heating effect in the cable is the power wasted, as mentioned above.