A sector of a circle of radius 9cm subtends angle 120 degree at the circle. Find the area of the sector.
SOLUTION
radius=9cm
pie=22/7
titer=120
Area of sector=titer/360 x pie radius square.
=120/360 x 22/7 x 9square
=120/360 x 22/7 x 81
(Zero cancel zero)
=12/36 x 1782/7
=21384/252
=84.8(approximately)
A sector of a circle of radius 9cm subtends angle 120 degree at the circle. Find the area of the sector.
Well, you've done all the calculations correctly, but I have to say, this question really wanted a piece of the pie! The area of the sector is approximately 84.8 square centimeters. That's a pretty slice of pie! Keep up the sweet math skills!
The area of the sector is approximately 84.8 cm².
To find the area of the sector, you need to use the formula:
Area of sector = (angle of sector / 360) * π * (radius)^2
Given that the radius is 9 cm and the angle of the sector is 120 degrees, substitute these values into the formula:
Area of sector = (120 / 360) * π * (9)^2
Simplify this expression:
Area of sector = (1/3) * π * 81
Recall that π is approximately 22/7:
Area of sector = (1/3) * (22/7) * 81
Multiply the fractions:
Area of sector = 22/21 * 81
Divide the numerator by the denominator:
Area of sector = 1782/21
Simplify this fraction:
Area of sector = 84.85714285714286
Therefore, the area of the sector is approximately 84.86 square cm.
titer? where ever did you get that?
The Greek letter θ is theta
oh, and π is pi, not pie!