A number cube is rolled 360 times and the results are recorded as follows: 41 ones, 54 twos, 62 threes, 75 fours, 33 fives, and 95 sixes. What is the experimental probability of rolling a two or a three?
Please help me figure out the answer all I need are steps helping me solve it <:)
THANK YOU!
and yes I AM STUCK FOR THE FIRST TIME ON A PROBLEM!
the experiment yielded 54 twos and 62 threes out of 360 tries
p(2 or 3) = (54 + 62) / 360
thank you-
so the answer would be-
decimal: 0.184126984
work:
1.54+62=116
2. 116/360=0.184126984
(/ always means divide-)
my work right?
To find the experimental probability of rolling a two or a three, we need to find the total number of successful outcomes (rolling a two or a three) divided by the total number of trials (360 rolls of the number cube).
Step 1: Start by finding the total number of successful outcomes, which in this case are rolling a two or a three.
- The number of twos is 54.
- The number of threes is 62.
Step 2: Add the number of twos and threes together to find the total number of successful outcomes.
- 54 + 62 = 116
Step 3: Find the experimental probability by dividing the total number of successful outcomes by the total number of trials.
- Experimental Probability = Total Number of Successful Outcomes / Total Number of Trials
- Experimental Probability = 116 / 360
Step 4: Simplify the fraction, if possible.
- In this case, the fraction cannot be simplified further.
Therefore, the experimental probability of rolling a two or a three is 116/360.