In Brooke's class, 2⁄9 of the children have a pet lizard. Of the students who have a lizard, 2⁄3 also have a dog. What fraction of the children in Brooke's class have both a lizard and a dog?
What is (2/9)(2/3) ?
5/9
To find the fraction of children in Brooke's class who have both a lizard and a dog, we need to multiply the fractions representing the two scenarios: having a lizard and having a dog.
First, 2/9 of the children have a pet lizard.
Second, out of the students who have a lizard, 2/3 also have a dog.
To find the fraction of students who have both a lizard and a dog, we multiply 2/9 by 2/3.
(2/9) * (2/3) = (2 * 2) / (9 * 3) = 4/27
Therefore, the fraction of children in Brooke's class who have both a lizard and a dog is 4/27.
To find the fraction of children in Brooke's class who have both a lizard and a dog, we need to multiply the fractions representing the proportion of children with lizards and the proportion of children with both a lizard and a dog.
Let's assume there are 27 students in Brooke's class (since it is easy to work with multiples of 9 and 3). According to the information given, 2/9 of the children have a pet lizard. Therefore, (2/9) * 27 = 6 students have a pet lizard.
Of the students who have a lizard, 2/3 also have a dog. So, (2/3) * 6 = 4 students have both a lizard and a dog.
Now, let's calculate the fraction. We have 4 students with both a lizard and a dog out of 27 students in total.
Therefore, the fraction of children in Brooke's class who have both a lizard and a dog is 4/27.