A Point charge of 10.5uC is located inside a cube, what is the net electric flux?
LOL trick question
It does not matter what the shape is.
The total flux depends only on how much charge is inside. (Google Gauss Law)
4 pi * the charge inside
Come again? I'm a little bit slow in terms of understanding, it means it cannot be solve without its shape or length? Etc how about 3.5uC?
I can not give you a link but try searching with
wikipedia.org/wiki/Gauss's_law
The total flux out does not depend on the size or shape of the surface, only on how much charge is inside. As your distance from the charge goes up, E goes down at the same rate (1/r^2) as surface area goes up so the flux is the same. What comes out depends only on what is inside, not the size or shape of the container. It is as if you had a hose in there pouring out a gallon a minute. No matter what your containment shape, a gallon a minute comes through.
To calculate the net electric flux through a closed surface, such as a cube in this case, you need to apply Gauss's Law. Gauss's Law states that the net electric flux through a closed surface is equal to the electric charge enclosed divided by the permittivity of free space (ε₀).
The formula for Gauss's Law is:
Φ = Q_enclosed / ε₀
In this case, you are given a point charge of 10.5 μC (microcoulombs) located inside a cube. Note that the charge enclosed is the charge within the closed surface, which is given by the point charge.
Before calculating the flux, we need to convert the charge from microcoulombs (μC) to coulombs (C). 1 μC is equal to 10^-6 C, so:
Charge (Q) = 10.5 μC * (10^-6 C/1 μC) = 10.5 * 10^-6 C = 1.05 * 10^-5 C
Now, we need to determine the permittivity of free space, denoted as ε₀. The value of ε₀ is a constant equal to approximately 8.85 x 10^-12 C²/(N·m²).
Now, we can calculate the net electric flux through the cube using the formula:
Φ = Q / ε₀
Φ = (1.05 * 10^-5 C) / (8.85 x 10^-12 C²/(N·m²))
To simplify the calculation, divide the numerator by the denominator:
Φ = (1.05 * 10^-5 C) * (1/(8.85 x 10^-12 C²/(N·m²)))
Φ = (1.05 * 10^-5 C) * (1/(8.85 x 10^-12 C²/(N·m²))) = (1.05 * 10^-5 C) * (1/(8.85 x 10^-12 C²/(1/(N·m²))))
Φ ≈ 1.18 N·m²/C²
Therefore, the net electric flux through the cube is approximately 1.18 N·m²/C².