CURVE SKETCHING

𝑦 = π‘₯2 + 2

ANSWER: 𝐢𝑃: π‘₯ = 0 , No IP, Decreasing on (βˆ’βˆž, 0), Increasing on (0, ∞) , CU on (βˆ’βˆž, ∞) ,
Minimum point (0,2)

y = x^2+2

surely you know this a parabola, with vertex at (0,2)
so y is increasing for x > 0 and decreasing left of the vertex

But if you want to go through the calculus,
y' = 2x
so y is increasing for y' > 0. That is, 2x>0

y" = 2, so it is never zero

I WANT THE STEPS PLEASE