In Einstein’s analysis, a photon striking the surface of a conductor is absorbed by an electron. Which statement describes the set of energy transfers that could occur?
A. The electron receives either all or none of the photon's energy.
B. The electron may receive any fraction of the photon's energy, including all or none of it. *
C. The electron may receive only certain quantized amounts of the photon's energy, including all or none of it.
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A photon has an energy of 5.66 eV. What is its wavelength? Let Planck’s constant h = 4.136 × 10^−15 eV · s, and the speed of light c = 3.00 × 10^8 m/s.
A. 219 nm
B. 384 nm
C. 513 nm
D. 710 nm* (I'm torn between D and C, but I'm going with D for this question)
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8. Glycerine has an index of refraction of 1.473, and liquid water has an index of refraction of 1.333. What is the critical angle for light passing from glycerine to liquid water? *
8.049°
25.71°
64.82°*
19.45°
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The line spectrum of an atom includes a band of red light of wavelength 705 nm (705 x 10^-9 m). This band corresponds to what energy transition within the atom? Let Planck’s constant h = 4.136 × 10−15 eV • s, and the speed of light c = 3.00 × 10^8 m/s. *
an increase of 3.87 eV*
a decrease of 2.27 eV
a decrease of 1.76 eV
a decrease of 9.06 eV
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The index of refraction of medium 1 is 2.3 and the index of refraction for medium 2 is 1.6. What is the critical angle for light traveling within medium 1 toward medium 2?
A. 40°*
B. 70°
C. 14°
D. 44°
Please help me double check my answers. Thank you.
The index of refraction of medium 1 is 2.3 and the index of refraction for medium 2 is 1.6. What is the critical angle for light traveling within medium 1 toward medium 2?
A. 40°*
B. 70°
C. 14°
D. 44°
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To answer the questions, let's go through each one and explain how to get the answers.
1. In Einstein's analysis, a photon striking the surface of a conductor is absorbed by an electron. The question asks which statement describes the set of energy transfers that could occur:
A. The electron receives either all or none of the photon's energy.
B. The electron may receive any fraction of the photon's energy, including all or none of it.
C. The electron may receive only certain quantized amounts of the photon's energy, including all or none of it.
The correct answer is B. According to Einstein's analysis, the electron may receive any fraction of the photon's energy, including all or none of it.
2. The question asks about the wavelength of a photon with an energy of 5.66 eV. We can use the formula E = hc/λ, where E is the energy, h is Planck's constant, c is the speed of light, and λ is the wavelength.
Plugging in the given values:
5.66 eV = (4.136 × 10^-15 eV · s) * (3.00 × 10^8 m/s) / λ
Rearranging the formula to solve for λ:
λ = (4.136 × 10^-15 eV · s) * (3.00 × 10^8 m/s) / 5.66 eV
Calculating the value of λ:
λ ≈ 2.199 × 10^-7 m
Converting the wavelength to nanometers:
λ ≈ 219 nm
Therefore, the answer is A. The wavelength of the photon is approximately 219 nm.
3. The question asks for the critical angle for light passing from glycerine (index of refraction = 1.473) to liquid water (index of refraction = 1.333).
The formula to calculate the critical angle is θc = sin^(-1)(n2/n1), where n1 is the index of refraction of medium 1 and n2 is the index of refraction of medium 2.
Plugging in the given values:
θc = sin^(-1)(1.333/1.473)
Calculating the value of θc using a scientific calculator:
θc ≈ 64.82°
Therefore, the answer is C. The critical angle for light passing from glycerine to liquid water is approximately 64.82°.
4. The question asks about the energy transition within an atom that corresponds to a band of red light with a wavelength of 705 nm.
To calculate the energy transition, we can use the formula E = hc/λ, where E is the energy, h is Planck's constant, c is the speed of light, and λ is the wavelength.
Plugging in the given values:
E = (4.136 × 10^-15 eV · s) * (3.00 × 10^8 m/s) / (705 × 10^-9 m)
Calculating the value of E:
E ≈ 3.87 eV
Therefore, the answer is A. The band of red light with a wavelength of 705 nm corresponds to an increase of approximately 3.87 eV in energy transition within the atom.
5. The question asks for the critical angle for light traveling within medium 1 (index of refraction = 2.3) toward medium 2 (index of refraction = 1.6).
Using the formula θc = sin^(-1)(n2/n1), where n1 is the index of refraction of medium 1 and n2 is the index of refraction of medium 2:
θc = sin^(-1)(1.6/2.3)
Calculating the value of θc using a scientific calculator:
θc ≈ 40°
Therefore, the answer is A. The critical angle for light traveling within medium 1 toward medium 2 is approximately 40°.