For what value of m would the functions f(x)= −mx +5 and g(x)= mx2−4x +1 have exactly one point of intersection?
mx2−4x +1 = −mx +5
mx^2 + x(m-4) - 4 = 0
to have ONE roots, b^2 a- 4ac = 0
(m-4)^2 - 4(m)(-4) = 0
(m-4)^2 = -16m
m^2 - 8m + 16 = -16m
m^2 + 8m + 16 = 0
(m+4)^2 = 0
m+4 = 0
m = -4