A bag contains 4 blue marbles, 10 green marbles, and 11 yellow marbles. Twice you draw a marble and replace it. Find P(yellow, then blue).

please help c:

11/25 x 4/25 = 44/625

To find the probability of drawing a yellow marble and then a blue marble, we need to determine:

1. The probability of drawing a yellow marble on the first draw.
2. The probability of drawing a blue marble on the second draw, given that we replaced the first marble.

Let's calculate each probability step-by-step:

1. Probability of drawing a yellow marble on the first draw:
The total number of marbles in the bag is 4 (blue) + 10 (green) + 11 (yellow) = 25. The probability of drawing a yellow marble on the first draw is:
P(yellow on first draw) = (Number of yellow marbles) / (Total number of marbles)
= 11 / 25
= 0.44 (rounded to two decimal places)

2. Probability of drawing a blue marble on the second draw, given the replacement:
Since we replaced the first marble back into the bag, the total number of marbles remains the same (25). Now, we calculate the probability of drawing a blue marble on the second draw:
P(blue on second draw) = (Number of blue marbles) / (Total number of marbles)
= 4 / 25
= 0.16 (rounded to two decimal places)

To find the probability of both events occurring (yellow on first draw, then blue on second draw), we multiply the individual probabilities:
P(yellow, then blue) = P(yellow on first draw) * P(blue on second draw)
= 0.44 * 0.16
= 0.0704 (rounded to four decimal places)

Therefore, the probability of drawing a yellow marble on the first draw and then a blue marble on the second draw, with replacement, is approximately 0.0704.

Hope it helped UwU

tysm!!! llife saver

the two drawings are independent events

... the probability of both is the product of the individual probabilities

P(yellow) = 11 / 25

P(blue) = 4 / 25