A = 3/5, cos B = 8/17 and A and B are acute angles, determine the exact value of tan A tan
I will assume that the first part is supposed to say
sinA = 3/4
for each case, make a sketch of the corresponding right-angled triangle
for A , given sinA = 3/5
x = ? , y = 3, hyp = 5
x^2 + 9 = 25
x = 4 , so cosA = 4/5
for B , cosB = 8/17
x = 8 , y = ?, hyp = 17
64 + y^2 = 289
y = 15 , so sinB = 15/17
tanA = sinA/cosA = (3/5) / (4/5) = 3/4 or .75
tanB = sinB/cosB = (15/17) / (8/17) = 15/8 = 1.875
I will let you figure out what you mean by "tan A tan"