How to find the equation of the axis of parabola and its length of the latus rectum having y-x²+8x=0?
y + 16 = x^2 - 8 x + 16 (x-4)^2 = y + 16 = 4(1/4)(y+16) vertex at (4,-16) axis of symmetry is x = 4 latus rectum = 4 (1/4) = 1
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