Multiplicative inverse of 7 is:
A:1/7
B:7
C:2/7
D:1
suppose you multipy
7 by 15 to get 105
what would you have to multiply 105 by to get back to 15 ?
A:1/7
B:7
C:2/7
D:1
7 by 15 to get 105
what would you have to multiply 105 by to get back to 15 ?