If pH is 5, what is H+ and OH-?
If pOH is 3, what is H+ and OH-?
pH is the negative log of the H+ concentration
... pOH is the negative log of the OH- concentration
pH + pOH = 14
for pH 5 ... [H+] = 10^-5 ... [OH-] = 10^-9
you can use online calculators for this stuff
To determine the concentrations of H+ (hydrogen ion) and OH- (hydroxide ion) in a solution based on the given pH or pOH values, we need to use the equations relating pH and pOH to the concentrations of H+ and OH- ions.
1. If pH is 5:
- pH = -log[H+]
- Rearranging the equation, we have [H+] = 10^(-pH)
- Substituting the given pH value of 5, we get [H+] = 10^(-5)
- By using a scientific calculator or logarithmic tables, we find that [H+] = 0.00001 M.
Since water is neutral, the concentration of OH- ions will be equal to [H+] in pure water (at 25°C) since [H+] = [OH-] in a neutral solution.
Therefore, [OH-] = 0.00001 M.
2. If pOH is 3:
- pOH = -log[OH-]
- Rearranging the equation, we have [OH-] = 10^(-pOH)
- Substituting the given pOH value of 3, we get [OH-] = 10^(-3)
- By using a scientific calculator or logarithmic tables, we find that [OH-] = 0.001 M.
Since water is neutral, the concentration of H+ ions will be equal to [OH-] in pure water (at 25°C) since [H+] = [OH-] in a neutral solution.
Therefore, [H+] = 0.001 M.
So, for a pH of 5, [H+] = 0.00001 M and [OH-] = 0.00001 M.
For a pOH of 3, [H+] = 0.001 M and [OH-] = 0.001 M.