A drawer contains 4 red socks, 7 white socks, and 11 blue socks. Without looking, you draw out a sock and then draw out a second sock without returning the first sock.
Find P(red, then white).
7/121
1/44
2/33
2/11
A drawer contains 4 red socks, 7 white socks, and 11 blue socks. Without looking, you draw out a sock and then draw out a second sock without returning the first sock.
Find P(red, then white).
7/121
1/44
2/33
2/11
22 socks in all, so
4/22 * 7/21
oops, didn't mean to send it twice, my bad
thanks
To find the probability of drawing a red sock and then a white sock without replacement, we need to calculate two probabilities:
1. The probability of drawing a red sock on the first draw: There are a total of 4 red socks out of 22 socks in the drawer, so the probability of drawing a red sock on the first draw is 4/22.
2. The probability of drawing a white sock on the second draw, given that a red sock was already drawn and not replaced: After the first draw, there are now 21 socks left in the drawer, with 7 white socks. So the probability of drawing a white sock on the second draw, given that a red sock was already drawn, is 7/21.
To find the overall probability of drawing a red sock and then a white sock, we multiply the two probabilities:
P(red, then white) = (4/22) * (7/21) = 2/33.
Therefore, the correct answer is 2/33.