Find the solutions of the system algebraically
𝑦 = 𝑥^2 + 1
𝑦 = 𝑥+1
a. (0, 1) 𝑎𝑛𝑑 (1, 2)
b. (0, 1) 𝑎𝑛𝑑 (−1, 2)
c. (0, −1) 𝑎𝑛𝑑 (1, 2)
d. No solution
x^2 + 1 = x + 1 ... x^2 = x
there are two numbers that equal their own squares ... 0 and 1
𝑦 = 𝑥^2 + 1
𝑦 = 𝑥+1
a. (0, 1) 𝑎𝑛𝑑 (1, 2)
b. (0, 1) 𝑎𝑛𝑑 (−1, 2)
c. (0, −1) 𝑎𝑛𝑑 (1, 2)
d. No solution
there are two numbers that equal their own squares ... 0 and 1