Drink Survey
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Drink | Number of Shoppers Who Preferred It
A | 10
B | 15
C | 7
D | 3
E | 6
What is the probability that 1 shopper, selected at random, preferred neither Drink E nor Drink C?
13/41
13/28
35/41
28/41
I also need help with this
A standard number cube is rolled 288 times. Predict how many times a 3 or a 5 will be the result.
96 times
93 times
99 times
58 times
Drink Survey
---------------------
Drink | Number of Shoppers Who Preferred It
A | 10
B | 15
C | 7
D | 3
E | 6
What is the probability that 1 shopper, selected at random, preferred neither Drink E nor Drink C?
13/41
13/28
35/41
28/41
What is the probability that neither tile is purple?
The probability of drawing a non-purple tile on the first draw is:
= (number of non-purple tiles) / (total number of tiles)
= (4 + 6) / (4 + 6 + 10)
= 10/20
= 1/2
Since the first tile is not returned, the number of tiles remaining in the box for the second draw will depend on the color of the first tile drawn. If the first tile drawn is non-purple, there will be 9 purple tiles and a total of 19 tiles for the second draw. If the first tile drawn is purple, there will be 8 purple tiles and a total of 18 tiles for the second draw.
The probability of drawing a non-purple tile on the second draw, given that the first tile drawn was non-purple, is:
= (number of remaining non-purple tiles) / (total number of remaining tiles)
= (4 + 6 - 1) / (19 - 1)
= 9/18
= 1/2
The probability of drawing a non-purple tile on the second draw, given that the first tile drawn was purple, is:
= (number of remaining non-purple tiles) / (total number of remaining tiles)
= (4 + 6) / (18 - 1)
= 10/17
The combined probability of drawing two non-purple tiles is:
= (probability of non-purple on first draw) * (probability of non-purple on second draw, given first draw was non-purple) + (probability of purple on first draw) * (probability of non-purple on second draw, given first draw was purple)
= (1/2) * (1/2) + (10/20) * (10/17)
= 1/4 + 25/68
= 47/136
Therefore, the probability that neither tile is purple is 47/136.
13/41
A 3 or 5 will occur 1/3 of the time.
i wish i could help but im bad at math
wow, you are smart PsyDAG
Thanks
Drink Survey
---------------------
Drink | Number of Shoppers Who Preferred It
A | 10
B | 15
C | 7
D | 3
E | 6
What is the probability that 1 shopper, selected at random, preferred neither Drink E nor Drink C?
13/41
13/28
35/41
28/41
To find the probability that a shopper preferred neither Drink E nor Drink C, we need to first find the total number of shoppers who preferred drinks other than E and C.
Total number of shoppers who preferred drinks other than E and C = Number of shoppers who preferred A + Number of shoppers who preferred B + Number of shoppers who preferred D
= 10 + 15 + 3
= 28
Therefore, the probability that 1 shopper, selected at random, preferred neither Drink E nor Drink C is:
Number of shoppers who preferred neither E nor C/Total number of shoppers = 28/41
So, the answer is 28/41.