A hot air balloon is rising upwards at a constant velocity of 5m.s,when the balloon is 60mabove the ground ,a sandbag is released from it and allowed to free fall ,ignore the effects of air
1 describe the motion of sandbag when it was dropped free fall
When the sandbag is released from the hot air balloon, it will experience free fall. Free fall occurs when an object is falling under the sole influence of gravity, without any air resistance. In this situation, the sandbag will accelerate downwards at a constant rate of 9.8 m/s², which is the acceleration due to gravity on Earth.
2 Calculate the time it takes for the sandbag to reach the ground.
To calculate the time it takes for the sandbag to reach the ground, we can use the equation of motion:
h = (1/2) gt²
Where:
h = height (60 m in this case)
g = acceleration due to gravity (9.8 m/s²)
t = time
Rearranging the equation, we get:
t = sqrt(2h/g)
Plugging in the given values:
t = sqrt(2 * 60 m / 9.8 m/s²)
t = sqrt(12.24 s²)
t ≈ 3.5 seconds
Therefore, it will take approximately 3.5 seconds for the sandbag to reach the ground.
3 Calculate the final velocity of the sandbag just before it hits the ground.
To calculate the final velocity of the sandbag just before it hits the ground, we can use the equation of motion:
v = gt
Where:
v = final velocity
g = acceleration due to gravity (9.8 m/s²)
t = time (3.5 seconds in this case)
Plugging in the given values:
v = 9.8 m/s² * 3.5 s
v ≈ 34.3 m/s
Therefore, the sandbag will have a final velocity of approximately 34.3 m/s just before it hits the ground.