Can you guys help me make a cosine Limaçons? They have to have the same a and b value.
The general polar form a Limaçon is
r = a + bcos(c theta)
(for your case it looks like you want c = 1)
Here is a picture of r = 2 + 4cos(theta)
www.wolframalpha.com/input/?i=r+%3D+2+%2B+4cos%28theta%29
(copy and paste this into a new window)
play with it by changing the values of a and b
try making one or both negatives or even decimals
for some really fun stuff place a multiplier in front of theta,
e.g..
try r = 3 + 4cos(5theta)