A jar contains 2 orange, 4 green, 2 white and 2 black balls. What is the probability of drawing an orange ball without putting it back, then drawing a black ball? (write your answer as a simplified fraction) *
10 balls in all, so
2/10 * 2/9 = ____
To find the probability of drawing an orange ball without replacement and then drawing a black ball, you need to determine the total number of possible outcomes and the number of favorable outcomes.
Step 1: Determine the total number of possible outcomes
The total number of balls in the jar is 2 orange + 4 green + 2 white + 2 black = 10 balls.
Step 2: Determine the number of favorable outcomes
Since you are drawing without replacement, the number of orange balls reduces to 1 after the first draw. Therefore, the number of favorable outcomes for the second draw (drawing a black ball) is 2 black.
Step 3: Calculate the probability
The probability is calculated by dividing the number of favorable outcomes by the number of total outcomes.
Probability = Number of favorable outcomes / Number of total outcomes
Number of favorable outcomes = 1 orange * 2 black = 2
Number of total outcomes = 10 balls * 9 balls (after one orange is drawn) = 90
Probability = 2 / 90
The probability of drawing an orange ball without putting it back, then drawing a black ball is 2/90. This fraction cannot be further simplified.