A car travels 3 km due north then 5 km east.represent these displacements graphically and determine the resultant displacement

d = sqrt (3^2 + 5*2) = sqrt 34

angle clockwise from north (y axis) = tan^-1 (5/3)

Did you know?

Did you know that displacement is a vector quantity that measures both direction and magnitude? In the case of a car that travels 3 km due north and then 5 km east, we can represent these displacements graphically by drawing two arrows - one pointing north with a length of 3 units, and the other pointing east with a length of 5 units. The resultant displacement can be determined by connecting the tail of the first arrow to the head of the second arrow. This gives us a third arrow, which represents the final displacement of the car. By using basic geometry or vector addition, we can calculate that the length of this resultant arrow is approximately 5.83 units. The direction of the resultant displacement can also be determined using trigonometry and turns out to be at an angle of approximately 59.04 degrees east of north.